IB Maths HL, SL, Studies: Trigonometry, Trigonometric equations, IB Math HL

Wednesday, January 29, 2014

Trigonometry, Trigonometric equations, IB Math HL

IB Mathematics HL – Trigonometry, Trigonometric equations, tanx

How can we solve the following trigonometric equation?

$tan^2x=1$ in the interval $[0,2\pi]$ .

The solution

IB Math HL – Trigonometry, Trigonometric equations

$tan^2x=1 \Rightarrow tanx=1 \ or tanx=-1$

First we’ll solve the trigonometric equation $tanx=1$

$tanx=1 \Rightarrow x=\frac{\pi}{4} \ or x=\pi+\frac{\pi}{4}=\frac{5\pi}{4}$

and then the other trigonometric equation $tanx=-1$ .

$x= \frac{3\pi}{4} \ or x=2\pi-\frac{\pi}{4}=\frac{7\pi}{4}$

Therefore, the solutions are

$x=\frac{\pi}{4} , \frac{5\pi}{4} , \frac{3\pi}{4} , \frac{7\pi}{4}$

Question and answer is here
http://www.ibmaths4u.com/viewtopic.php?f=3&t=438

IB math questions and answers by www.ibmaths4u.com

IB Maths HL, SL, Studies

Wednesday, January 29, 2014

Trigonometry, Trigonometric equations, IB Math HL

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